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patch 9.0.0449: there is no easy way to translate a key code into a string

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Problem:    There is no easy way to translate a string with a key code into a
            readable string.
Solution:   Add the keytrans() function. (closes #11114)
This commit is contained in:
zeertzjq
2022-09-12 13:38:41 +01:00
committed by Bram Moolenaar
parent 5a4eb55122
commit cdc839353f
9 changed files with 83 additions and 15 deletions
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6
src/map.c
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@@ -2317,7 +2317,7 @@ mapblock2dict(
int buffer_local, // false if not buffer local mapping
int abbr) // true if abbreviation
{
char_u *lhs = str2special_save(mp->m_keys, TRUE);
char_u *lhs = str2special_save(mp->m_keys, TRUE, FALSE);
char_u *mapmode = map_mode_to_chars(mp->m_mode);
dict_add_string(dict, "lhs", lhs);
@@ -2409,7 +2409,7 @@ get_maparg(typval_T *argvars, typval_T *rettv, int exact)
if (*rhs == NUL)
rettv->vval.v_string = vim_strsave((char_u *)"<Nop>");
else
rettv->vval.v_string = str2special_save(rhs, FALSE);
rettv->vval.v_string = str2special_save(rhs, FALSE, FALSE);
}
}
@@ -2478,7 +2478,7 @@ f_maplist(typval_T *argvars UNUSED, typval_T *rettv)
keys_buf = NULL;
did_simplify = FALSE;
lhs = str2special_save(mp->m_keys, TRUE);
lhs = str2special_save(mp->m_keys, TRUE, FALSE);
(void)replace_termcodes(lhs, &keys_buf, flags, &did_simplify);
vim_free(lhs);