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patch 8.2.2227: Vim9: recognizing lambda is too complicated

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Problem:    Vim9: recognizing lambda is too complicated.
Solution:   Call compile_lambda() and check for NOTDONE.
This commit is contained in:
Bram Moolenaar
2020-12-27 14:43:30 +01:00
parent 7e3ee7823f
commit e462f52db3
4 changed files with 25 additions and 59 deletions
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18
src/testdir/test_vim9_expr.vim
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@@ -1863,9 +1863,9 @@ def Test_expr7_lambda()
END
CheckDefAndScriptSuccess(lines)
CheckDefFailure(["var Ref = {a->a + 1}"], 'E720:')
CheckDefFailure(["var Ref = {a-> a + 1}"], 'E720:')
CheckDefFailure(["var Ref = {a ->a + 1}"], 'E720:')
CheckDefFailure(["var Ref = {a->a + 1}"], 'E1004:')
CheckDefFailure(["var Ref = {a-> a + 1}"], 'E1004:')
CheckDefFailure(["var Ref = {a ->a + 1}"], 'E1004:')
CheckDefFailure(["filter([1, 2], {k,v -> 1})"], 'E1069:', 1)
# error is in first line of the lambda
@@ -1964,13 +1964,9 @@ def Test_expr7_new_lambda()
END
CheckDefAndScriptSuccess(lines)
CheckDefFailure(["var Ref = (a)=>a + 1"], 'E1001:')
CheckDefFailure(["var Ref = (a)=> a + 1"], 'E1001:')
CheckDefFailure(["var Ref = (a) =>a + 1"], 'E1001:')
CheckScriptFailure(["vim9script", "var Ref = (a)=>a + 1"], 'E1004:')
CheckScriptFailure(["vim9script", "var Ref = (a)=> a + 1"], 'E1004:')
CheckScriptFailure(["vim9script", "var Ref = (a) =>a + 1"], 'E1004:')
CheckDefAndScriptFailure(["var Ref = (a)=>a + 1"], 'E1004:')
CheckDefAndScriptFailure(["var Ref = (a)=> a + 1"], 'E1004:')
CheckDefAndScriptFailure(["var Ref = (a) =>a + 1"], 'E1004:')
CheckDefFailure(["var Ref: func(number): number = (a: number): string => 'x'"], 'E1012:')
CheckDefFailure(["var Ref: func(number): string = (a: number): string => 99"], 'E1012:')
@@ -2682,7 +2678,7 @@ func Test_expr7_fails()
call CheckDefFailure(["'yes'->", "Echo()"], 'E488: Trailing characters: ->', 1)
call CheckDefExecFailure(["[1, 2->len()"], 'E697:', 2)
call CheckDefExecFailure(["{a: 1->len()"], 'E723:', 2)
call CheckDefExecFailure(["{a: 1->len()"], 'E1004:', 1)
call CheckDefExecFailure(["{['a']: 1->len()"], 'E723:', 2)
endfunc