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patch 8.2.0615: regexp benchmark stest is old style
Problem: Regexp benchmark stest is old style. Solution: Make it a new style test. Fix using a NULL list. Add more tests. (Yegappan Lakshmanan, closes #5963)
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@@ -794,18 +794,41 @@ func Test_mode()
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set complete&
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endfunc
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" Test for append()
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func Test_append()
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enew!
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split
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call append(0, ["foo"])
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call append(1, [])
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call append(1, test_null_list())
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call assert_equal(['foo', ''], getline(1, '$'))
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split
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only
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undo
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undo
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" Using $ instead of '$' must give an error
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call assert_fails("call append($, 'foobar')", 'E116:')
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endfunc
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" Test for setline()
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func Test_setline()
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new
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call setline(0, ["foo"])
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call setline(0, [])
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call setline(0, test_null_list())
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call setline(1, ["bar"])
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call setline(1, [])
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call setline(1, test_null_list())
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call setline(2, [])
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call setline(2, test_null_list())
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call setline(3, [])
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call setline(3, test_null_list())
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call setline(2, ["baz"])
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call assert_equal(['bar', 'baz'], getline(1, '$'))
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close!
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endfunc
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func Test_getbufvar()
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let bnr = bufnr('%')
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let b:var_num = '1234'
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@@ -913,6 +936,7 @@ func Test_match_func()
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call assert_equal(-1, match(['a', 'b', 'c', 'a'], 'a', 5))
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call assert_equal(4, match('testing', 'ing', -1))
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call assert_fails("let x=match('testing', 'ing', 0, [])", 'E745:')
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call assert_equal(-1, match(test_null_list(), 2))
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endfunc
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func Test_matchend()
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@@ -1796,6 +1820,7 @@ func Test_call()
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call assert_equal(3, 'len'->call([123]))
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call assert_fails("call call('len', 123)", 'E714:')
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call assert_equal(0, call('', []))
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call assert_equal(0, call('len', test_null_list()))
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function Mylen() dict
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return len(self.data)
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@@ -1962,7 +1987,6 @@ func Test_range()
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execute "normal! a\<C-r>=[complete(col('.'), range(10)), ''][1]\<CR>"
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" complete_info()
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execute "normal! a\<C-r>=[complete(col('.'), range(10)), ''][1]\<CR>\<C-r>=[complete_info(range(5)), ''][1]\<CR>"
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call assert_fails('call complete(1, ["a"])', 'E785:')
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" copy()
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call assert_equal([1, 2, 3], copy(range(1, 3)))
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