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patch 8.2.3900: it is not easy to use a script-local function for an option

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Problem:    It is not easy to use a script-local function for an option.
Solution:   recognize s: and <SID> at the start of the expression. (Yegappan
            Lakshmanan, closes #9401)
This commit is contained in:
Yegappan Lakshmanan
2021-12-26 10:51:39 +00:00
committed by Bram Moolenaar
parent ec86520f94
commit 8bb65f230d
13 changed files with 265 additions and 8 deletions
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20
src/testdir/test_diffmode.vim
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@@ -681,8 +681,19 @@ func Test_diffexpr()
set diffexpr=NewDiffFunc()
call assert_fails('windo diffthis', ['E117:', 'E97:'])
diffoff!
" Using a script-local function
func s:NewDiffExpr()
endfunc
set diffexpr=s:NewDiffExpr()
call assert_equal(expand('<SID>') .. 'NewDiffExpr()', &diffexpr)
set diffexpr=<SID>NewDiffExpr()
call assert_equal(expand('<SID>') .. 'NewDiffExpr()', &diffexpr)
%bwipe!
set diffexpr& diffopt&
delfunc DiffExpr
delfunc s:NewDiffExpr
endfunc
func Test_diffpatch()
@@ -1216,10 +1227,19 @@ func Test_patchexpr()
call assert_equal(2, winnr('$'))
call assert_true(&diff)
" Using a script-local function
func s:NewPatchExpr()
endfunc
set patchexpr=s:NewPatchExpr()
call assert_equal(expand('<SID>') .. 'NewPatchExpr()', &patchexpr)
set patchexpr=<SID>NewPatchExpr()
call assert_equal(expand('<SID>') .. 'NewPatchExpr()', &patchexpr)
call delete('Xinput')
call delete('Xdiff')
set patchexpr&
delfunc TPatch
delfunc s:NewPatchExpr
%bwipe!
endfunc