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patch 7.4.2072

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Problem:    substitute() does not support a Funcref argument.
Solution:   Support a Funcref like it supports  a string starting with "\=".
This commit is contained in:
Bram Moolenaar
2016-07-19 19:10:51 +02:00
parent f562e72df7
commit 72ab729c3d
7 changed files with 82 additions and 17 deletions
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18
src/testdir/test_expr.vim
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@@ -135,3 +135,21 @@ function Test_printf_64bit()
call assert_equal("123456789012345", printf('%d', 123456789012345))
endif
endfunc
func Test_substitute_expr()
let g:val = 'XXX'
call assert_equal('XXX', substitute('yyy', 'y*', '\=g:val', ''))
call assert_equal('XXX', substitute('yyy', 'y*', {-> g:val}, ''))
call assert_equal("-\u1b \uf2-", substitute("-%1b %f2-", '%\(\x\x\)',
\ '\=nr2char("0x" . submatch(1))', 'g'))
call assert_equal("-\u1b \uf2-", substitute("-%1b %f2-", '%\(\x\x\)',
\ {-> nr2char("0x" . submatch(1))}, 'g'))
call assert_equal('231', substitute('123', '\(.\)\(.\)\(.\)',
\ {-> submatch(2) . submatch(3) . submatch(1)}, ''))
func Recurse()
return substitute('yyy', 'y*', {-> g:val}, '')
endfunc
call assert_equal('--', substitute('xxx', 'x*', {-> '-' . Recurse() . '-'}, ''))
endfunc