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patch 9.0.1617: charidx() result is not consistent with byteidx()

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Problem:    charidx() and utf16idx() result is not consistent with byteidx().
Solution:   When the index is equal to the length of the text return the
            lenght of the text instead of -1. (Yegappan Lakshmanan,
            closes #12503)
This commit is contained in:
Yegappan Lakshmanan
2023-06-08 17:09:45 +01:00
committed by Bram Moolenaar
parent 5bf042810b
commit 577922b917
6 changed files with 132 additions and 52 deletions
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17
src/strings.c
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@@ -1054,7 +1054,8 @@ byteidx_common(typval_T *argvars, typval_T *rettv, int comp UNUSED)
if (in_vim9script()
&& (check_for_string_arg(argvars, 0) == FAIL
|| check_for_number_arg(argvars, 1) == FAIL))
|| check_for_number_arg(argvars, 1) == FAIL
|| check_for_opt_bool_arg(argvars, 2) == FAIL))
return;
char_u *str = tv_get_string_chk(&argvars[0]);
@@ -1158,7 +1159,14 @@ f_charidx(typval_T *argvars, typval_T *rettv)
for (p = str, len = 0; utf16idx ? idx >= 0 : p <= str + idx; len++)
{
if (*p == NUL)
{
// If the index is exactly the number of bytes or utf-16 code units
// in the string then return the length of the string in
// characters.
if (utf16idx ? (idx == 0) : (p == (str + idx)))
rettv->vval.v_number = len;
return;
}
if (utf16idx)
{
idx--;
@@ -1775,7 +1783,14 @@ f_utf16idx(typval_T *argvars, typval_T *rettv)
for (p = str, len = 0; charidx ? idx >= 0 : p <= str + idx; len++)
{
if (*p == NUL)
{
// If the index is exactly the number of bytes or characters in the
// string then return the length of the string in utf-16 code
// units.
if (charidx ? (idx == 0) : (p == (str + idx)))
rettv->vval.v_number = len;
return;
}
int clen = ptr2len(p);
int c = (clen > 1) ? utf_ptr2char(p) : *p;
if (c > 0xFFFF)