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patch 7.4.1464

Problem:    When the argument of sort() is zero or empty it fails.
Solution:   Make zero work as documented. (suggested by Yasuhiro Matsumoto)
This commit is contained in:
Bram Moolenaar
2016-02-29 22:05:26 +01:00
parent a6b8976bb7
commit 5131c144fe
3 changed files with 22 additions and 2 deletions

View File

@@ -19195,11 +19195,21 @@ do_sort_uniq(typval_T *argvars, typval_T *rettv, int sort)
goto theend; /* type error; errmsg already given */
if (i == 1)
info.item_compare_ic = TRUE;
else
else if (argvars[1].v_type != VAR_NUMBER)
info.item_compare_func = get_tv_string(&argvars[1]);
else if (i != 0)
{
EMSG(_(e_invarg));
goto theend;
}
if (info.item_compare_func != NULL)
{
if (STRCMP(info.item_compare_func, "n") == 0)
if (*info.item_compare_func == NUL)
{
/* empty string means default sort */
info.item_compare_func = NULL;
}
else if (STRCMP(info.item_compare_func, "n") == 0)
{
info.item_compare_func = NULL;
info.item_compare_numeric = TRUE;

View File

@@ -35,3 +35,11 @@ func Test_sort_nested()
" test ability to call sort() from a compare function
call assert_equal([1, 3, 5], sort([3, 1, 5], 'Compare1'))
endfunc
func Test_sort_default()
" docs say omitted, empty or zero argument sorts on string representation.
call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"]))
call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"], ''))
call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"], 0))
call assert_fails('call sort([3.3, 1, "2"], 3)', "E474")
endfunc

View File

@@ -743,6 +743,8 @@ static char *(features[]) =
static int included_patches[] =
{ /* Add new patch number below this line */
/**/
1464,
/**/
1463,
/**/