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patch 7.4.1464
Problem: When the argument of sort() is zero or empty it fails. Solution: Make zero work as documented. (suggested by Yasuhiro Matsumoto)
This commit is contained in:
14
src/eval.c
14
src/eval.c
@@ -19195,11 +19195,21 @@ do_sort_uniq(typval_T *argvars, typval_T *rettv, int sort)
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goto theend; /* type error; errmsg already given */
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goto theend; /* type error; errmsg already given */
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if (i == 1)
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if (i == 1)
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info.item_compare_ic = TRUE;
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info.item_compare_ic = TRUE;
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else
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else if (argvars[1].v_type != VAR_NUMBER)
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info.item_compare_func = get_tv_string(&argvars[1]);
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info.item_compare_func = get_tv_string(&argvars[1]);
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else if (i != 0)
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{
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EMSG(_(e_invarg));
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goto theend;
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}
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if (info.item_compare_func != NULL)
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if (info.item_compare_func != NULL)
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{
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{
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if (STRCMP(info.item_compare_func, "n") == 0)
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if (*info.item_compare_func == NUL)
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{
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/* empty string means default sort */
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info.item_compare_func = NULL;
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}
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else if (STRCMP(info.item_compare_func, "n") == 0)
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{
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{
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info.item_compare_func = NULL;
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info.item_compare_func = NULL;
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info.item_compare_numeric = TRUE;
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info.item_compare_numeric = TRUE;
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@@ -35,3 +35,11 @@ func Test_sort_nested()
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" test ability to call sort() from a compare function
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" test ability to call sort() from a compare function
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call assert_equal([1, 3, 5], sort([3, 1, 5], 'Compare1'))
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call assert_equal([1, 3, 5], sort([3, 1, 5], 'Compare1'))
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endfunc
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endfunc
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func Test_sort_default()
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" docs say omitted, empty or zero argument sorts on string representation.
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call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"]))
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call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"], ''))
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call assert_equal(["2", 1, 3.3], sort([3.3, 1, "2"], 0))
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call assert_fails('call sort([3.3, 1, "2"], 3)', "E474")
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endfunc
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@@ -743,6 +743,8 @@ static char *(features[]) =
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static int included_patches[] =
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static int included_patches[] =
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{ /* Add new patch number below this line */
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{ /* Add new patch number below this line */
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/**/
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1464,
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/**/
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/**/
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1463,
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1463,
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/**/
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/**/
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