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updated for version 7.4.176

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Problem:    Dictionary.update() thows an error when used without arguments.
            Python programmers don't expect that.
Solution:   Make Dictionary.update() without arguments do nothing. (ZyX)
This commit is contained in:
Bram Moolenaar
2014-02-11 18:47:27 +01:00
parent cd981f2e0f
commit 2d5f38ff10
4 changed files with 12 additions and 2 deletions
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10
src/if_py_both.h
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@@ -1918,11 +1918,17 @@ DictionaryUpdate(DictionaryObject *self, PyObject *args, PyObject *kwargs)
}
else
{
PyObject *obj;
PyObject *obj = NULL;
if (!PyArg_ParseTuple(args, "O", &obj))
if (!PyArg_ParseTuple(args, "|O", &obj))
return NULL;
if (obj == NULL)
{
Py_INCREF(Py_None);
return Py_None;
}
if (PyObject_HasAttrString(obj, "keys"))
return DictionaryUpdate(self, NULL, obj);
else